NAME¶

stpcpy - copy a string returning a pointer to its end

SYNOPSIS¶

#include <string.h>

char *stpcpy(char *dest, const char *src);

stpcpy():

DESCRIPTION¶

The stpcpy() function copies the string pointed to by src (including the terminating null byte ('\0')) to the array pointed to by dest. The strings may not overlap, and the destination string dest must be large enough to receive the copy.

RETURN VALUE¶

stpcpy() returns a pointer to the end of the string dest (that is, the address of the terminating null byte) rather than the beginning.

ATTRIBUTES¶

For an explanation of the terms used in this section, see attributes(7).

CONFORMING TO¶

This function was added to POSIX.1-2008. Before that, it was not part of the C or POSIX.1 standards, nor customary on UNIX systems. It first appeared at least as early as 1986, in the Lattice C AmigaDOS compiler, then in the GNU fileutils and GNU textutils in 1989, and in the GNU C library by 1992. It is also present on the BSDs.

BUGS¶

This function may overrun the buffer dest.

EXAMPLES¶

For example, this program uses stpcpy() to concatenate foo and bar to produce foobar, which it then prints.

#define _GNU_SOURCE
#include <string.h>
#include <stdio.h>
int
main(void)
{


    char buffer[20];


    char *to = buffer;


    to = stpcpy(to, "foo");


    to = stpcpy(to, "bar");


    printf("%s\n", buffer);
}

SEE ALSO¶

bcopy(3), memccpy(3), memcpy(3), memmove(3), stpncpy(3), strcpy(3), string(3), wcpcpy(3)

COLOPHON¶

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